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If 16^r is equivalent to 4^-1/t, what is the value of rt? A. -0.5 B. 0.5 C. -1 D. 1

1 Answer

2 votes

Answer:

A

Explanation:

using the rule of exponents


(a^m)^(n) =
a^(mn)

given


16^(r)
4^{(-1)/(t) }


(4^2)^(r)
4^{(-1)/(t) }


4^(2r) =
4^{(-1)/(t) }

since the bases on both sides are 4, then equate the exponents

2r =
(-1)/(t) ( multiply both sides by t to clear the fraction )

2rt =- 1 ( divide both sides by 2 )

rt =
(-1)/(2) = - 0.5

answered
User Graham Griffiths
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