Question

What impulse occurs when an average force of 5.0 N is exerted on a cart for 2.8 s?

Answer 1

14 N*s

Step-by-step explanation:

Δp = FΔt (Impulse Equation, change in momentum = force * change in time)

Δp = 5 * (2.8 - 0)

Δp = 14 N*s