asked 163k views
3 votes
a chef want to make 1 gallon (128) ounces of a 5% vinegar-to-oil salad dressing. He only had pure vinegar and a mild 4% vinegar-to-oil salad dressing on hand. How many ounces of each should he mix to make the desired dressing? (Round your answers to two decimal places)

1 Answer

2 votes

Answer:

  • 1.33 oz pure vinegar
  • 126.67 oz 4% dressing

Explanation:

You want the number of ounces each of pure vinegar and 4% vinegar-to-oil salad dressing to mix to make 128 ounces of 5% dressing.

Setup

Let v represent the number of ounces of pure vinegar in the mix. Then (128-v) is the number of ounces of 4% dressing. The amount of vinegar in the mix is then ...

1.00v +0.04(128 -v) = 0.05(128)

Solution

Simplifying the above equation, we have ...

0.96v +5.12 = 6.4 . . . . . . . . . . eliminate parentheses

0.96v = 1.28 . . . . . . . . . . . . . subtract 5.12

v = 1.28/0.96 = 4/3 ≈ 1.33 . . . . . divide by 0.96

(128 -v) = 126.67

The chef should use 1.33 ounces of pure vinegar with 126.67 ounces of 4% dressing.

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answered
User IMaddin
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