asked 108k views
4 votes
What is the final temperature of 180.1 g of water (specific heat = 4.18 J/g・°C) at 24.20°C that absorbed 950.0 J of heat?

1 Answer

4 votes

Answer:

temperature of the water is approximately 25.533°C.

Step-by-step explanation:

To find the final temperature of the water, we can use the formula:

q = mcΔT

Where q is the heat absorbed, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

Given:

q = 950.0 J

m = 180.1 g

c = 4.18 J/g・°C

Initial temperature (T1) = 24.20°C

First, let's calculate ΔT:

ΔT = q / (mc)

ΔT = 950.0 J / (180.1 g * 4.18 J/g・°C)

ΔT ≈ 1.333 °C

To find the final temperature (T2), we add the change in temperature (ΔT) to the initial temperature (T1):

T2 = T1 + ΔT

T2 = 24.20°C + 1.333°C

T2 ≈ 25.533°C

Therefore, the final temperature of the water is approximately 25.533°C.

answered
User Shaahin Ashayeri
by
8.0k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.