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A car initially traveling 14.0ft/s, steadily speeds up to 48.0ft/s in 7.00s. Determine all the unknowns and answer the following question.

How far did the car travel during this time?

1 Answer

3 votes

Answer:

Vavg = 34/7ft/s, D = 34ft

Step-by-step explanation:


distance= ((average velocity)/(time) )


V_(avg) = (48-14)/(7) = (34)/(7)


D = V * t = (34)/(7) * 7 = 34 ft

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User Ootterskog
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