Question

Find a polynomial with real coefficients that has the given zeros.

- 1 and 2-3i
P(x) = x³ - 3x² + blank x+ 13.

Answer 1

Hi,

Explanation:

P(x)=(x+1)(x-(2-3i))(x-(2+3i))

=(x+1)(x^2-4x+2^2+3^2)=(x+1)(x^2-4x+13)

=x^3-4x^2+13x+x^2-4x+13

=x^3-3x^2+9x+13

blank=9