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The width of a brick is half the​ length, which is 2 inches less than eight times the height. if the sum of the three dimensions is 26.25 ​inches, find the volume of the brick.

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User Szxk
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8.3k points

1 Answer

3 votes

Answer:

Volume = 0.84 in^3

Explanation:

Let W and L be the Width and Length of the brick. Let H be the height.

We are told that "The width of a brick is half the​ length," which we can write as:

W = (1/2)L

We also learn that the length, L, is 2 inches less than 8 times the height. This can be written as:

L = 8*H - 2"

We finally learn that "the sum of the three dimensions is 26.25 ​inches," which converts into the following:

W + L + H = 26.25"

We want the volume: Volume = W*L*H

We'll need to use substitution to eliminate two of the variables to get a start on the other two unknowns. We can see from the two first equations that both contain the variable L. Let's rearrange them to find how the second variable is a function of L:

W = (1/2)L (already arranged for W =)

---

L = 8*H - 2"

8*H = L + 2"

H = (L + 2")/8

==

Now use these two definitions of W and H in the third equation:

W + L + H = 26.25"

(1/2)L + L + ((L + 2")/8) = 26.25"

4L + 8L + L+ 2' = 26.25" [Multiply both sides by 8]

13L = 24.25"

L = 1.87"

--

Since W = (1/2)L

W = (1/2)*(1.87")

W = 0.933"

Since H = (L + 2")/8

H = (1.87" + 2")/8

H = (3.87")/8

H = 0.484"

Volume = W*L*H

Volume = (0.933")*(1.87")*(0.484")

Volume = 0.84 in^3

answered
User Adam Cox
by
8.7k points

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