Question

The endpoints of WX are W (5Ė-3) and X (-1Ė-9) .

YA
H
.co
-10 -8
-6
A.
What is the length of WX?
6
B. 12
C. 16
7
D. 2√3
E. 6√/2
-2
10
-2
-4
-8
-10
2
4
W
8
10

Answer 1

Answer is E

Explanation:

To find the length of the line segment with endpoints W(5, -3) and X(-1, -9), you can use the distance formula, which is derived from the Pythagorean theorem in two-dimensional space. The distance formula is:

`\[d = √((x_2 - x_1)^2 + (y_2 - y_1)^2)\]`

In your case,
`\(x_1 = 5\), \(y_1 = -3\), \(x_2 = -1\), and \(y_2 = -9\).`Plug these values into the formula:

`\[d = √((-1 - 5)^2 + (-9 - (-3))^2)\]`

Now, simplify the expression inside the square root:

`\[d = √((-6)^2 + (-6)^2)\]`

`\[d = √(36 + 36)\]`

`\[d = √(72)\]`

Since
`\(√(72)\)` is equal to
`\(6√(2)\)`, the length of the line segment WX is
`(6√(2)\)` units.

Answer 2

`\sf E. 6√(2)`

Explanation:

Given:

• X(-1,-9)
• W(5,-3)

To find:

`\sf \textsf{ Length of } \overline{WX} =?`

Solution:

In order to find the length of
`\sf \overline{WX}`, we can use the distance formula:

`\sf Distance = √((x_2 - x_1)^2 + (y_2 - y_1)^2)`

where
`\sf (x_1, y_1)` and
`\sf (x_2, y_2)` are the coordinates of the two points.

In this case, we have:

`\sf (x_1, y_1) = (-1, -9)`

`\sf (x_2, y_2) = (5, -3)`\sf

Substituting these values into the distance formula, we get:

`\sf Distance \overline{WX}= √((5 - (-1))^2 + (-3 - (-9))^2)`

`\sf Distance \overline{WX}= √((6)^2 + (6)^2)`\sf

`\sf Distance \overline{WX}= √(36 + 36)`

`\sf Distance \overline{WX}= √(72)`

`\sf Distance \overline{WX}=6√(2)`

Therefore, the length of
`\sf \overline{WX}` is:

`\sf E. 6√(2)`