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1/4 of a certain number is added to 4 1/3. The sum is the same as when 1/3 of it is subtracted from 20 2/3. Find the number​

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Answer:

Let's call the certain number "N."

According to the problem, 1/4 of N is added to 4 1/3, which can be represented as:

(1/4)N + 4 1/3

And this sum is equal to when 1/3 of N is subtracted from 20 2/3:

20 2/3 - (1/3)N

Now, we can set up an equation with these two expressions being equal:

(1/4)N + 4 1/3 = 20 2/3 - (1/3)N

First, let's convert all the mixed numbers to improper fractions:

4 1/3 = 13/3

20 2/3 = 62/3

Now, the equation becomes:

(1/4)N + 13/3 = 62/3 - (1/3)N

Next, we can simplify the equation by getting rid of fractions. Multiply both sides of the equation by 12 (the least common multiple of 4 and 3) to eliminate the fractions:

12 * [(1/4)N + 13/3] = 12 * [62/3 - (1/3)N]

3N + 52 = 248 - 4N

Now, let's isolate the N terms on one side and the constants on the other:

3N + 4N = 248 - 52

7N = 196

Now, divide both sides by 7 to solve for N:

N = 196 / 7

N = 28

So, the certain number is 28.

answered
User Purushottam
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