asked 206k views
3 votes
The length of a rectangular room is 3.5 feet less than the twice the

width. The perimeter of the room is 53 feet. What is the width of the
room?
O 19.5 ft
O 11.5 ft
O 16.5 ft
O 10 ft

and then what is the length

asked
User Aspirant
by
8.5k points

1 Answer

2 votes

Answer:

Width = 10 feet

Length = 16.5 feet

Explanation:

We can determine the length and width of the room using a system of equations where:

  • L represents the room's length,
  • and W represents its width.

First equation:

The formula for the perimeter of a rectangle is given by:

P = 2L + 2W, where

  • P is the perimeter,
  • L is the length,
  • and W is the width.

Since we're told that the room's perimeter is 53 feet, our first equation is given by:

53 = 2L + 2W

Second equation:

Since we're told that the room's length is 3.5 feet less than twice the width, our second equation is given by:

L = 2W - 3.5

Method to solve: Substitution:

Solving for W (the width):

Now we can solve for W (the width) by substituting 2W - 3.5 for L in the first equation in our system:

53 = 2(2W - 3.5) + 2W

53 = 4W - 7 + 2W

(53 = 6W - 7) + 7

(60 = 6W) / 6

10 = W

Thus, the width is 10 feet.

Solving for L (the length):

Now we can solve for L (the length) by plugging in 10 for W in the second equation in our system:

L = 2(10) - 3.5

L = 20 - 3.5

L = 16.5

Thus, the length is 16.5 feet.

answered
User Okken
by
8.4k points

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