Question

what is the equation of the line in slope-intercept form that passes through(-5,-2) and is perpendicular to 2x+4y=12

Answer 1

y = 2x + 8

Explanation:

2x+4y=12

4y = -2x + 12

y = -2x/4 + 12/4

y = -1/2x + 3

Slope of the perpendicular line: 2 (slope of perpendicular lines is negative reciprocal of each other)

m = 2 and point (-5,-2)

y-y = m ( x - x )

y - - 2 = 2 (x - - 5)

y + 2 = 2x + 10

y = 2x + 10 - 2

y = 2x + 8