Question

There are 3 Math tuition centres near a school. Zeeta tuitions has 40% more seats and Alpha tutors has th 1 more seats than Triumph centre. 4 If a total of 1825 students are there in these 3 tuition centres, how many seats are available at Zeeta tuitions?​

Answer 1

The total number of students in the three tuition centers is 1825. Let’s assume the number of seats at the Triumph center is x. According to the information given, Zeeta tuitions has 40% more seats than the Triumph center, which means Zeeta tuitions has 1.4x seats. Alpha tutors has 1 more seat than the Triumph center, which means Alpha tutors has x + 1 seats1.

To find the number of seats at Zeeta tuitions, we can set up an equation:

x + (1.4x) + (x + 1) = 1825.

Simplifying the equation, we have:

3.4x + 1 = 1825.

Subtracting 1 from both sides of the equation, we get:

3.4x = 1824.

Dividing both sides of the equation by 3.4, we find:

x ≈ 536.47.

Since we can’t have a fraction of a seat, we round down to the nearest whole number. Therefore, there are approximately 536 seats at the Triumph center1.

To find the number of seats at Zeeta tuitions, we can substitute this value back into our equation:

1.4 * 536 ≈ 750.4.

Rounding down to the nearest whole number, there are approximately 750 seats at Zeeta tuitions

Explanation: