Question

2. Dylan and Bailey are selling pies for a team fundraiser. Dylan sold 5 apple pies and 3 peach pies for a t

$22. Bailey sold 3 apple pies and 4 peach pies for a total of $22. Find the cost of each type of pie.
(Let P = peach pies and A - apple pies)

Answer 1

Explanation:

If P is the number of peach pies, and A is the number of apple pies, then:

5A + 3P = 22

3A + 4P = 22

Solve the system of equations using substitution or elimination. If we multiply the first equation by 4 and the second equation by 3:

20A + 12P = 88

9A + 12P = 66

Subtract:

11A = 22

A = 2

Now plug into any equation to find P.

3(2) + 4P = 22

6 + 4P = 22

4P = 16

P = 4

Each apple pie is $2 and each peach pie is $4.

Answer 2

• P = $4
• A = $2

Task :

• To find the cost of each type of pie

Solution :

Let the peach pies be P and the apple ones be A.

ATQ,

Dylan sold 5P & 3A for $22.

The following can be written as

• 3P + 5A = $22.....(1)

and,

Bailey sold 4P & 3A for $22 which can be also written as

• 4P + 3A = $22.....(2)

Multiplying equation (1) by 4 and equation (2) by 3, we get,

• 12P + 20A = $88....(3)
• 12P + 9A = $66...(4)

Subtracting equation (4) from equation (3), we get,

• 11A = $22
• A = $22/11
• A = $2

Thus, the cost of each apple pie is $2.

Plugging in the value of A in equation (1),

• 3P + 5($2) = $22
• 3P + $10 = $22
• 3P = $22 - $10
• 3P = $12
• P = $12/3
• P = $4

Therefore,the cost of each peach pie is $4.

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