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(G ° F)(-2) where G(x)=x^2 and F(x)=2x+3

2 Answers

5 votes
The answer is -4x^3 + 6x^2

1. Multiply the polynomial (x^2)(2x + 3) which is 2x^3 - 3x^2
2. Multiply that by (-2) which gives us our answer :)
answered
User Mynd
by
9.0k points
2 votes

Answer:


\sf (G \circ F) (-2) = \boxed{1}

Explanation:

To find:


\sf (G \circ F) (-2) = ?

Given:


\sf G(x)=x^2


\sf F(x)=2x+3

Solution:


\sf (G \circ F) (-2) = G(F(-2))

In order to find
\sf (G \circ F) (-2) , we first need to find the value of F(-2).

Then, we can substitute that value into G(x) to find the final answer.


\sf F(-2) = (2)(-2) + 3 = -4 + 3 = -1

Now that we know F(-2) = -1, we can substitute that value into G(x) to find
\sf (G \circ F) (-2).


\sf G(-1) = (-1)^2 = 1

Therefore,
\sf (G \circ F) (-2) = \boxed{\sf 1}

answered
User Veridian
by
7.4k points

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