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What is (14x^2 - 41x + 15) ÷ (7x - 3)?

What is (14x^2 - 41x + 15) ÷ (7x - 3)?
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What is (14x^2 - 41x + 15) ÷ (7x - 3)?

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User Pkozlov
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1 Answer

7 votes

Answer:

Explanation:

The result of dividing (14x^2 - 41x + 15) by (7x - 3) is 2x - 5, with a remainder of 0.

Therefore, the quotient is 2x - 5.

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User Salvina
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