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What is the ph of 500 ml 10.0 nm naoh aqueous solution under standard situations?

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Answer:

The pH of a 10.0 M (molar) NaOH (sodium hydroxide) aqueous solution under standard conditions can be calculated using the formula for pH:

pH = -log10([H+])

In this case, since you have a strong base, you need to find the concentration of hydroxide ions ([OH-]) in the solution, and then calculate the pH.

NaOH is a strong base, and when it dissociates in water, it forms one hydroxide ion (OH-) for each molecule of NaOH. So, the concentration of hydroxide ions is 10.0 M.

Now, calculate the pH:

pH = -log10(10.0)

pH = -1

So, the pH of a 10.0 M NaOH aqueous solution under standard conditions is -1.

Step-by-step explanation:

answered
User Yatish Mehta
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