Question

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Answer 1

Certainly! Here are the steps to simplify √28 + 3√63:

Step 1: Find the prime factorization of the numbers under the radicals.

- √28 = √(2^2 * 7) = 2√7

- 3√63 = 3√(3^2 * 7) = 9√7

Step 2: Add the simplified radicals together.

- 2√7 + 9√7 = (2 + 9)√7 = 11√7

So, √28 + 3√63 simplifies to 11√7.

Answer 2

`\sf 11√(7)`

Explanation:

`\sf √(28) + 3√(63)`

To simplify this, we can first factor the perfect squares out of the radicals:

`\sf √(28) + 3√(63)`

First step

`√(4 \cdot 7) + 3√(9 \cdot 7)`

Then, we can simplify the radicals:

Second step:

`\sf √(2\cdot 2 \cdot7) + 3 \cdot √(3\cdot 3\cdot 7)`

Third step:

`\sf 2√(7) + 3 \cdot 3√(7)`

Forth step:

Finally, we can combine the terms:

`\sf (2 + 3 \cdot 3) √(7)`

and Final step:

`\sf 11√(7)`

Therefore, the simplified form of expressions is
`\sf 11√(7)`