Answer:
THERE
Explanation:
a) To determine how far each ostrich ran, we need to calculate the area under the velocity-time graph for each ostrich. Since the graph represents velocity, the area under the graph represents the distance traveled.
For Ostrich Bert:
The area under the graph can be divided into two sections: a triangle and a rectangle. The triangle's base is 3 seconds and its height is 18 m/s, so its area is (1/2) * 3 * 18 = 27 m. The rectangle has a base of 2 seconds and a height of 9 m/s, so its area is 2 * 9 = 18 m. Adding the areas together, Bert ran a total distance of 27 + 18 = 45 meters.
For Ostrich Ernie:
The area under the graph can also be divided into two sections: a triangle and a rectangle. The triangle's base is 4 seconds and its height is 12 m/s, so its area is (1/2) * 4 * 12 = 24 m. The rectangle has a base of 2 seconds and a height of 6 m/s, so its area is 2 * 6 = 12 m. Adding the areas together, Ernie ran a total distance of 24 + 12 = 36 meters.
b) To calculate the average velocity of Bert, we need to divide the total distance he ran (45 meters) by the total time it took (5 seconds). Therefore, Bert's average velocity is 45 meters / 5 seconds = 9 m/s.
c) The initial acceleration of Ernie can be determined by finding the slope of the velocity-time graph during the initial portion. From the graph, we can see that Ernie's velocity increases by 6 m/s over the first 2 seconds. Therefore, his initial acceleration is (change in velocity) / (change in time) = 6 m/s / 2 seconds = 3 m/s^2.
d) Without further calculation, we can determine that Ernie had the greatest initial acceleration. This is because Ernie's velocity increases at a steeper slope during the initial part of the graph compared to Bert's velocity. The greater the slope, the greater the acceleration. Therefore, Ernie had the greatest initial acceleration.