Question

Find the answer of this problem..................

Answer 1

x^2 - 2x - 35 = 0

Explanation:

[(x-3)(3x+4)] - [(x+2)(x-3)] = 64

(3x^2 + 4x - 9x - 12) - (x^2-3x+2x-6) = 64

2x^2 - 5x + x - 6 = 64

2x^2 - 4x -6 = 64

2x^2 - 4x = 70

2x^2 -4x - 70 = 0

2 (x^2 - 2x - 35 = 0

x^2 - 2x - 35 = 0/2

x^2 - 2x - 35 = 0