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Helppp please!!!!!....

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Answer:

To compare the electrostatic force between Sphere A with a charge of +3 microcoulombs (µC) and Sphere B with a charge of +9 microcoulombs (µC), we can use Coulomb's law, which describes the relationship between the electrostatic force (F), the charges (q1 and q2), and the distance (r) between them:

=

1

2

2

F=

r

2

k∗∣q1∗q2∣

Where:

F is the electrostatic force.

k is Coulomb's constant, approximately equal to

8.99

×

1

0

9

N

m

2

/

C

2

8.99×10

9

N⋅m

2

/C

2

.

1

q1 and

2

q2 are the charges of the two objects.

r is the distance between the centers of the two spheres.

Let's assume the distance between the centers of the two spheres is constant at

r (i.e., they are not moving closer or farther apart).

For Sphere A (+3 µC) and Sphere B (+9 µC):

=

(

+

3

µC

)

(

+

9

µC

)

2

=

27

µC

2

2

F

AB

=

r

2

k∗∣(+3µC)∗(+9µC)∣

=

r

2

27∗kµC

2

Now, let's compare this with another scenario, where both Sphere A and Sphere B have the same charge, say +3 µC each:

=

(

+

3

µC

)

(

+

3

µC

)

2

=

9

µC

2

2

F

AA

=

r

2

k∗∣(+3µC)∗(+3µC)∣

=

r

2

9∗kµC

2

Now, let's compare

F

AB

and

F

AA

:

F

AB

is larger because the product of the charges (+3 µC and +9 µC) is greater than the product of the charges (+3 µC and +3 µC) in F_{AA. Therefore, the electrostatic force between Sphere A (+3 µC) and Sphere B (+9 µC) is stronger than the electrostatic force between two spheres with the same charge of +3 µC each.

Step-by-step explanation:

answered
User Liggi
by
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