Answer:
To compare the electrostatic force between Sphere A with a charge of +3 microcoulombs (µC) and Sphere B with a charge of +9 microcoulombs (µC), we can use Coulomb's law, which describes the relationship between the electrostatic force (F), the charges (q1 and q2), and the distance (r) between them:
�
=
�
∗
∣
�
1
∗
�
2
∣
�
2
F=
r
2
k∗∣q1∗q2∣
Where:
F is the electrostatic force.
k is Coulomb's constant, approximately equal to
8.99
×
1
0
9
N
⋅
m
2
/
C
2
8.99×10
9
N⋅m
2
/C
2
.
�
1
q1 and
�
2
q2 are the charges of the two objects.
�
r is the distance between the centers of the two spheres.
Let's assume the distance between the centers of the two spheres is constant at
�
r (i.e., they are not moving closer or farther apart).
For Sphere A (+3 µC) and Sphere B (+9 µC):
�
�
�
=
�
∗
∣
(
+
3
µC
)
∗
(
+
9
µC
)
∣
�
2
=
27
∗
�
µC
2
�
2
F
AB
=
r
2
k∗∣(+3µC)∗(+9µC)∣
=
r
2
27∗kµC
2
Now, let's compare this with another scenario, where both Sphere A and Sphere B have the same charge, say +3 µC each:
�
�
�
=
�
∗
∣
(
+
3
µC
)
∗
(
+
3
µC
)
∣
�
2
=
9
∗
�
µC
2
�
2
F
AA
=
r
2
k∗∣(+3µC)∗(+3µC)∣
=
r
2
9∗kµC
2
Now, let's compare
�
�
�
F
AB
and
�
�
�
F
AA
:
�
�
�
F
AB
is larger because the product of the charges (+3 µC and +9 µC) is greater than the product of the charges (+3 µC and +3 µC) in F_{AA. Therefore, the electrostatic force between Sphere A (+3 µC) and Sphere B (+9 µC) is stronger than the electrostatic force between two spheres with the same charge of +3 µC each.
Step-by-step explanation: