Question

consider the line y= 3x-4. Find the equation of the line that is parallel to this line and passes through the point (-4,5) Find the equation of the line that is perpendicular to this line and passes through the point(-4,5)

Answer 1

y = 3x + 17

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given the line

y = 3x - 4 ← in slope- intercept form

with slope m = 3

• Parallel lines have equal slopes , then

y = 3x + c ← is the partial equation

to find c, substitute the point (- 4, 5 ) into the partial equation

5 = 3(- 4) + c = - 12 + c ( add 12 to both sides )

17 = c

y = 3x + 17 ← equation of parallel line