Question

Determine the value(s) of "x" such that the equation [x^2]⎡⎣⎢4−5−4−5−1−3−42−3⎤⎦⎥⎡⎣⎢x−10⎤⎦⎥=[0] holds. a) x = 2 and x = 4 b) x = 10 and x = 12 c) x = 6 and x = 8 d) x = -2 and x = 0

Answer 1

Answer:a^x (X) b^x = ab^x, Exp. 2^4 x 3^4 = 6^4 12^5 = 2^10 x 3^5 12^5 = (2^2x3)^5 distribute the 5 12^5 = 2^10 x 3^5

Explanation: