If events A and B are independent with P(A) = 0.20 and P(A and B) = 0.12, what is the probability of event B as a percentage (rounded to two decimal places if necessary)?

Question

asked Feb 3, 2024 167k views

1 Answer

Adam Pflantzer · Answer 1 · 2024-02-07T17:03:03+0000

Work Shown

x = value of P(B)

P(A and B) = P(A)*P(B) only when A and B are independent

0.12 = 0.20*x

x = 0.12/0.20

x = 0.60

P(B) = 0.60 = 60%