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A force of 2.5KN is required to lift a load. How much work is done if the load is lifted through 500cm

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To calculate the work done in lifting a load, you can use the following formula:

Work (W) = Force (F) × Distance (d) × cos(θ)

Where:

Force (F) is the applied force, in newtons (N).

Distance (d) is the distance over which the force is applied, in meters (m).

θ is the angle between the direction of the force and the direction of the displacement. If the force is applied in the vertical direction and the lift is vertical, then θ is 0 degrees and the cos(θ) is 1.

In this case, the force is 2.5 kN, which is equivalent to 2500 N (1 kN = 1000 N), the distance is 500 cm, which is equivalent to 5 meters (since 1 meter = 100 centimeters), and θ is 0 degrees because you are lifting the load vertically.

Now you can calculate the work:

W = 2500 N × 5 m × cos(0°)

Since cos(0°) equals 1, you can simplify further:

W = 2500 N × 5 m × 1 = 12,500 N·m

Work is measured in joules (J), so you can express the result in joules:

W = 12,500 J

So, the work done in lifting the load 500 cm with a force of 2.5 kN is 12,500 joules.

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