Final answer:
Option b) 200.0 ml of 0.40 M NaCl contains the largest number of chloride ions, with 0.080 moles.
Step-by-step explanation:
To determine which solution contains the largest number of chloride ions, we need to consider the moles of chloride ions present in each solution. Moles of chloride ions can be calculated by multiplying the volume of the solution (in liters) by the molarity of the chloride compound.
Option a) 150 ml of 0.20 M AlCl₃: Moles of chloride ions = (0.150 L) x (0.20 mol/L) = 0.030 mol
Option b) 200.0 ml of 0.40 M NaCl: Moles of chloride ions = (0.200 L) x (0.40 mol/L) = 0.080 mol
Option c) 75 ml of 0.40 M MgCl₂: Moles of chloride ions = (0.075 L) x (0.40 mol/L) = 0.030 mol
Therefore, option b) 200.0 ml of 0.40 M NaCl contains the largest number of chloride ions, with 0.080 moles.