Question

2 H 2 O 2 ⟶ 2 H 2 O + O 2 If you collect 4.64 mL of O 2 at 298 K and 1.00 atm over 60.0 seconds from a reaction solution of 4.90 mL, what is the initial rate of the reaction?

Answer 1

The initial rate of the decomposition reaction of hydrogen peroxide (H2O2) to water (H2O) and oxygen (O2) is found by dividing the volume of oxygen produced over time. In this case, the initial reaction rate is 0.0773 mL/sec.

Step-by-step explanation:

The subject of this question is Chemistry, specifically the topic of chemical reaction rates. The initial rate of a reaction measures how the concentration of reactants or products changes over a specific period of time at the start of the reaction. In this case, we are asked to find the initial rate at which oxygen (O2) is produced in the decomposition reaction of hydrogen peroxide (H2O2).

To calculate the initial rate, we can use the volume of O2 gas produced over time. You have collected 4.64 mL of O2 over 60.0 seconds. Therefore, by dividing the volume of O2 collected by the time it was collected, we find the initial reaction rate is 4.64 mL/60.0 sec = 0.0773 mL/sec.

This is the rate at which O2 is produced from the decomposition of H2O2 at the given conditions of temperature and pressure (298 K and 1.00 atm).

Learn more about Chemical Reaction Rates