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Find the 60th term of the arithmetic sequence −29,−49,−69,

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Answer: The 60th term of the arithmetic sequence -29, -49, -69, … is -1209.

Explanation:

The given arithmetic sequence is -29, -49, -69, …

To find the 60th term of this sequence, we need to use the formula for the nth term of an arithmetic sequence:

a_n = a_1 + (n - 1)d

where a_n is the nth term of the sequence, a_1 is the first term of the sequence, n is the number of terms in the sequence, and d is the common difference between consecutive terms.

In this case, a_1 = -29 and d = -20 (since each term is 20 less than the previous term). We want to find a_60, so we substitute n = 60 into the formula:

a_60 = -29 + (60 - 1)(-20) = -29 + 59(-20) = -29 - 1180 = -1209

Therefore, the 60th term of the arithmetic sequence -29, -49, -69, … is -1209.

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