Question

IF a over 2 + 1 is a, then the value of a over 12 + a over 6 + 1 is what!?!?
(ALGEBRA)

Answer 1

Explanation:

a/(2) + 1 = a Multiply thru by '2' to get

a + 2 = 2a Subtract 'a' from both sides of the equation

2 = a

then (12 + a) /(6 + 1) = 14/7= 2 Possibly...

....you didn't include parentheses anywhere in your post ....so I assumed where they might be to get a reasonable answer

Here is the answer for what is actually posted :

a/2 + 1 = a shows a = 2 as before

12 + 2/ 6 + 1 = 12 + 1/3 + 1 = 13 1/3

Answer 2

Let's break it down step by step:

1. We're given that a/2 + 1 = a.
2. Now, we want to find the value of a/12 + a/6 + 1.

First, we can solve the equation in step 1 for 'a':
a/2 + 1 = a

Subtract 'a/2' from both sides:
1 = a - a/2

Now, find a common denominator for 'a' and 'a/2' (which is 2):
1 = (2a/2) - (a/2)

Combine the fractions on the right side:
1 = (2a - a) / 2

Simplify the right side:
1 = a / 2

Now, we have a value for 'a':
a = 2

Next, substitute this value into the expression from step 2:
a/12 + a/6 + 1

Replace 'a' with 2:
2/12 + 2/6 + 1

Now, simplify the fractions:
1/6 + 2/6 + 1

Combine the fractions on the left side:
(1/6 + 2/6) + 1

Now, add the fractions in the parentheses:
3/6 + 1

Simplify the fraction 3/6 (which is equivalent to 1/2):
1/2 + 1

Finally, add the fractions:
1/2 + 1 = 3/2

So, the value of a/12 + a/6 + 1 is 3/2.