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What is the density of salt, given that a 905-mg sample has a volume of 419uL?

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User Jahooma
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1 Answer

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To calculate the density of salt, we need to divide the mass of the sample by its volume. Let's go through the calculation step by step:

1. Convert the mass of the sample to grams:

- The given mass is 905 mg. To convert it to grams, we divide it by 1000: 905 mg ÷ 1000 = 0.905 g.

2. Convert the volume of the sample to liters:

- The given volume is 419 μL. To convert it to liters, we divide it by 1,000,000: 419 μL ÷ 1,000,000 = 0.000419 L.

3. Calculate the density:

- Density is calculated by dividing the mass (in grams) by the volume (in liters). In this case, the mass is 0.905 g and the volume is 0.000419 L. So, the density of the salt sample is: 0.905 g ÷ 0.000419 L ≈ 2166.44 g/L.

Therefore, the density of the salt sample is approximately 2166.44 g/L.

I hope this explanation helps you understand how to calculate the density of a sample. Let me know if you have any further questions.

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User Mechenbier
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