To calculate the percent of BaO in the mixture, we need to determine the moles of BaO and CaO, and then calculate the ratio of BaO to the total moles.
Given:
Mass of the mixture = 29.0 g
Volume of HCl used = 100.8 mL
Molarity of HCl = 6.00 M
First, we need to calculate the moles of HCl used:
Moles of HCl = Molarity * Volume (converted to liters)
Moles of HCl = 6.00 M * 0.1008 L
Moles of HCl = 0.6048 mol
Since the reaction is a 1:1 ratio between HCl and BaO, the moles of BaO will be equal to the moles of HCl used.
Next, we can calculate the moles of BaO:
Moles of BaO = Moles of HCl
Moles of BaO = 0.6048 mol
To calculate the percent of BaO in the mixture, we need to compare the moles of BaO to the total moles of the mixture.
The total moles of the mixture can be found using the molar mass of BaO:
Molar mass of BaO = 137.33 g/mol + 16.00 g/mol = 153.33 g/mol
Moles of BaO = Mass of BaO / Molar mass of BaO
Moles of BaO = 29.0 g / 153.33 g/mol
Moles of BaO = 0.1891 mol
Now, we can calculate the percent of BaO:
Percent of BaO = (Moles of BaO / Total moles) * 100%
Percent of BaO = (0.6048 mol / (0.6048 mol + 0.1891 mol)) * 100%
Percent of BaO = 0.7613 * 100%
Percent of BaO = 76.13%
Therefore, the percent of BaO in the mixture is approximately 76.13%. Option d) 80.0% is the closest answer.