asked 106k views
0 votes
If we model a cell as a sphere with radius r0, it has a surface area a0. if the size of the cell changes so that its radius is r0/2, what is its new surface area?

1 Answer

6 votes

Final answer:

When the radius of a sphere is halved, its surface area becomes one-fourth of the original surface area. The new surface area of the cell when its radius becomes r0/2 is πr0^2.

Step-by-step explanation:

If we model a cell as a sphere with radius r0, it has a surface area a0. To find the new surface area when the size of the cell changes such that its radius becomes r0/2, we need to calculate the new surface area a1.

The surface area of a sphere can be calculated using the formula a = 4πr^2, where a is the surface area and r is the radius.

Now, if the original radius is r0 and the new radius is r0/2, we substitute these values into the formula to calculate the new surface area:
a1 = 4π(r0/2)^2 = 4π(r0^2/4) = πr0^2

Therefore, the new surface area of the cell is a1 = πr0^2.

Learn more about Surface area of a sphere

answered
User MrAdib
by
8.0k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.