To determine how many moles of O2 would be consumed if 13.673 grams of V (vanadium) were consumed in a chemical reaction, you'll first need to know the balanced chemical equation for the reaction. I'll assume the reaction is as follows:
V + O2 → VO2
From the balanced equation, you can see that 1 mole of V reacts with 1 mole of O2 to form 1 mole of VO2. This means that the mole ratio of V to O2 is 1:1.
Now, calculate the number of moles of V in 13.673 grams:
Moles of V = Mass (grams) / Molar mass (g/mol)
The molar mass of V is the atomic mass of vanadium, which is approximately 50.94 g/mol.
Moles of V = 13.673 g / 50.94 g/mol ≈ 0.2684 moles
Since the mole ratio of V to O2 is 1:1, the number of moles of O2 consumed will also be approximately 0.2684 moles.
So, 0.2684 moles of O2 would be consumed if 13.673 grams of V were consumed in the reaction.