Question

A student from his window measures the angle of elevation of the top of a vertical pole to be 60° and the angle of depression of the bottom to be 30°. If the pole is 12 m away, calculate the height of the pole ​

Answer 1

(6√3 + 6) m

Explanation:

Given:

AC = 12 m

∠BAC = 60°

∠CAD = 30°

BC = AB sin 60°

= 12 ×
`(1)/(2) √(3)`

= 6√3 m

CD = AB sin 30°

= 12 ×
`(1)/(2)`

= 6 m

Height of the pole = BD + CD

= (6√3 + 6) m