What is the specific heat of a substance that absorbs 2.5 x 10^3 joules of heat when a sample of 1.0 x 10^4 g of the substance increases in temperature from 10.0°C to 70.0°C?

Question

asked Apr 8, 2024 186k views

1 Answer

Betoharres · Answer 1 · 2024-04-12T01:06:27+0000

The specific heat capacity of the substance is approximately 0.035 J/g°C.

The specific heat capacity of a substance can be calculated using the equation:

Q = mcΔT

Where:

Q = heat absorbed or released

m = mass of the substance

c = specific heat capacity of the substance

ΔT = change in temperature

Substituting the given values into the equation:

2.5 × 10^3 J = (1.0 × 10^4 g) × c × (70.0°C - 10.0°C)

Simplifying, we can find the specific heat capacity:

c = 2.5 × 10^3 J / ((1.0 × 10^4 g) × (70.0°C - 10.0°C))

Therefore, the specific heat capacity of the substance is calculated to be:

c ≈ 0.035 J/g°C