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AB has endpoints at (2, 3) and (2,5). After a dialation with a center at the origin and a scale factor of 1/5. What would be the length of the image of AB? a. 1/5 units b. 2/5 units c. 2 units d. 10 units

1 Answer

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To find the length of the image of AB after a dilation with a center at the origin and a scale factor of 1/5, you can use the distance formula:

Distance = √((x2 - x1)^2 + (y2 - y1)^2)

The endpoints of AB are (2, 3) and (2, 5). The dilation with a scale factor of 1/5 means that both the x-coordinate and the y-coordinate of each point will be multiplied by 1/5.

For the first point, (2, 3), after dilation:

x1' = 2 * (1/5) = 2/5

y1' = 3 * (1/5) = 3/5

For the second point, (2, 5), after dilation:

x2' = 2 * (1/5) = 2/5

y2' = 5 * (1/5) = 1

Now, you can calculate the distance between the two transformed points:

Distance = √((x2' - x1')^2 + (y2' - y1')^2)

Distance = √((2/5 - 2/5)^2 + (1 - 3/5)^2)

Distance = √(0^2 + (2/5)^2)

Distance = √(4/25)

Distance = 2/5

So, the length of the image of AB after dilation is 2/5 units, which corresponds to option (b).

answered
User Raju Ahmed
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