Answer:
zeros are x = - 3 and x = 1
Explanation:
given
y = 3x² + 6x - 9 ← factor out 3 from each term on the right side
y = 3(x² + 2x - 3) ← factor the quadratic
y = 3(x + 3)(x - 1) ← in intercept form
to find the zeros equate each factor to zero and solve for x
x + 3 = 0 ( subtract 3 from both sides )
x = - 3
x - 1 = 0 ( add 1 to both sides )
x = 1
the zeros are then x = - 3 and x = 1