Final Answer:
The possible genotypes and phenotypes for a cross between PpYY and ppYy pea plants are as follows: the offspring will have purple flowers and yellow peas. The genotype of the offspring will be PpYy.
Step-by-step explanation:
In pea plants, the genes for flower color and pea color segregate independently. The genotype PpYY means the individual has one dominant allele for purple flowers (P) and two dominant alleles for yellow peas (Y). On the other hand, the genotype ppYy means the individual has two recessive alleles for white flowers (p) and one dominant allele for yellow peas (Y). When these two individuals are crossed, the resulting offspring will inherit one allele from each parent for each gene.
For the flower color gene (P/p), the offspring will inherit one allele from Pp and one allele from pp, resulting in a genotype of Pp. Since purple (P) is dominant over white (p), the phenotype will be purple flowers. Similarly, for the pea color gene (Y/y), the offspring will inherit one allele from YY and one allele from Yy, resulting in a genotype of Yy. Since yellow (Y) is dominant over green (y), the phenotype will be yellow peas.
So, the final genotype and phenotype of the offspring from the cross PpYY x ppYy will be PpYy with purple flowers and yellow peas.
To determine the possible combinations of alleles in the offspring, a Punnett square analysis would involve four squares (2x2), representing the possible combinations of alleles from the parents. Each square would show the potential genotypes of the offspring, taking into account the independent assortment of alleles for flower color and pea color.