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Find the 66th term of the arithmetic sequence t − 10 , 7 , 24 , . . .

asked
User Cerin
by
9.0k points

1 Answer

1 vote

Answer:

a₆₆ = 1095

Explanation:

the nth term of an arithmetic sequence is


a_(n) = a₁ + (n - 1)d

where a₁ is the first term , d the common difference and n the term number

here a₁ - 10 and d = a₂ - a₁ = 7 - (- 10) = 7 + 10 = 17

substitute these values into the nth term formula

a₆₆ = - 10 + (65 × 17) = - 10 + 1105 = 1095

answered
User Mootymoots
by
7.8k points

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