Question

Solve the system of equations: x + y = 1003 y + 43 = x (A) x = 480, y = 523 (B) x = 523, y = 480 (C) x = 1003, y = 0 (D) x = 0, y = 1003

Answer 1

B

Explanation:

given the 2 equations

x + y = 1003 → (1)

y + 43 = x → (2)

substitute y + 43 = x into (1)

y + 43 + y = 1003 ( simplify left side )

2y + 43 = 1003 ( subtract 43 from both sides )

2y + 43 - 43 = 1003 - 43 ( simplify both sides )

2y = 960 ( divide both sides by 2 )

`(2)/(2)` y =
`(960)/(2)` , that is

y = 480

substitute y = 480 into (2)

480 + 43 = x , then

523 = x

solution is x = 523 , y = 480