Question

Question 7 (1 point)

What is the solution to the system of equations using elimination method?
(8x + 14y = 4
(6x + 7y = 10
The solution is x=
Blank 1:
Blank 2:
(Blank1) and y=
(Blank2)

Answer 1

Answer: x= 4 and y = -2

Explanation:

8x + 14y = 4

6x + 7y = 10

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Eliminate the y variable because the coefficients have common factors.

The least common multiple is 14 between 7 and 14.

8x + 14y = 4

(6x + 7y = 10)*(-2)

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8x + 14y = 4

-12x - 14y = -20

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-4x = -16

X= 4

So

6x + 7y = 10

6*4 + 7y = 10

24 + 7y = 10

7y = -14

y = -2

X= 4 and y = -2

From MysticAlanCheng

Answer 2

8x+14y=4

6x+7y=10

(8x + 14a = 4

(6x + 7a = 10

by multiplying the 2nd equation by -2 we will eliminate a

-2(6x+7a)=10)--->-12x-14a=-20

8x+14a=4

-12x-14a=-20

--->-4x=-16

x=-16/-4=4

we calculate:

6x+7a=10

6*4+7a=10

24+7a=10

7a=10-24

a=-14/7=-2

solution :

x=4

a=-2

Explanation: