Question

if the triangle BKY is similar to the triangle TZY and the perimeter of BKY is 208, find the perimeter of TZY. ZY=40, YT=45, BY=72

Answer 1

130

Explanation:

Given similar triangles BKY and TZY with BY=72 and TY=45, you want to know the perimeter of ∆TZY when the perimeter of ∆BKY is 208.

Proportion

In similar triangles, the perimeters have the same proportion as corresponding sides:

P(∆TZY)/P(∆BKY) = TY/BY

P(∆TZY) = P(∆BKY)·TY/BY = 208·45/72 = 130

The perimeter of ∆TZY is 130 units.

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Additional comment

The other side lengths are ...

• BK = 72
• KY = 64
• TZ = 45

Angles K, Y, Z are about 63.6°, and angles T and B are about 52.8°.

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