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A semicircle pond has a radius of 5 ft what is the area of the pond to the nearest square foot

asked
User Rianjs
by
8.2k points

1 Answer

4 votes

Answer:

39ft^2

Explanation:

The radius for a simicircle is .5(pir^2)

r^2=5*5=25

pi*25=78.5398163397

78.5398163397/2=39.2699081699

Rounding to square foot it would be 39

answered
User Qubeuc
by
7.7k points

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