Answer:
Explanation:
To find the equation of a straight line that is parallel to the given line y = 3x + 5 and passes through the point (0, -1), we can use the slope-intercept form of a linear equation, which is y = mx + b, where m represents the slope of the line and b represents the y-intercept.
Since the line we are looking for is parallel to y = 3x + 5, it will have the same slope. The slope of y = 3x + 5 is 3.
Now, we have the slope (m = 3) and a point on the line (0, -1). We can substitute these values into the slope-intercept form to find the y-intercept (b):
-1 = 3(0) + b
Simplifying, we have:
-1 = b
Therefore, the y-intercept is -1.
Now, we have the slope (m = 3) and the y-intercept (b = -1). We can write the equation of the line:
y = 3x - 1
So, the equation of the straight line through (0, -1) that is parallel to y = 3x + 5 is y = 3x - 1.