Question

MODELING REAL LIFE An artist sells bowls and mugs

at two craft shows. At the first craft show, the bowls
cost $11 and the mugs cost $6. The artist's revenue is
represented by g (xĖy) = 11x + 6y. During the second
craft show, the artist sells the bowls for $10 and the
mugs for $7.50. The revenue is represented by
R (xĖy) = 10x + 7.5y. The artist sells 25 mugs and
12 bowls at each craft show. Which craft show does
the artist earn more? Justify your answers.

Answer 1

Let’s calculate the revenue for each craft show:

For the first craft show, the revenue g(x, y) = 11x + 6y. If the artist sells 25 mugs (y) and 12 bowls (x), then the revenue is g(12, 25) = 11*12 + 6*25 = $282.

For the second craft show, the revenue R(x, y) = 10x + 7.5y. If the artist sells 25 mugs (y) and 12 bowls (x), then the revenue is R(12, 25) = 10*12 + 7.5*25 = $307.5.

Therefore, the artist earns more at the second craft show. The revenue from the second craft show is $307.5, which is higher than the $282 from the first craft show.