Question

Elvira made a trip on Tuesday, and David made the same trip on Wednesday, Elvira traveled at 14 mph. David traveled at 21 mph, shows time was 3 hours less than Elvira's time. How far did they travel?

Answer 1

Let's denote the time Elvira traveled as "t" hours. We know that David's time was 3 hours less, so David traveled for "t - 3" hours.

We also have their respective speeds:

- Elvira's speed = 14 mph
- David's speed = 21 mph

To find the distance each of them traveled, we can use the formula:

Distance = Speed × Time

For Elvira:
Distance (E) = 14 mph × t

For David:
Distance (D) = 21 mph × (t - 3)

Now, we can set up an equation based on the information given:

E = D

14t = 21(t - 3)

Now, let's solve for t:

14t = 21t - 63

Subtract 14t from both sides:

0 = 7t - 63

Add 63 to both sides:

7t = 63

Now, divide both sides by 7 to solve for t:

t = 63 / 7

t = 9

So, Elvira traveled for 9 hours. Now, we can find the distance:

Distance (E) = 14 mph × 9 hours = 126 miles

And for David:

Distance (D) = 21 mph × (9 - 3) hours = 21 mph × 6 hours = 126 miles

So, both Elvira and David traveled a distance of 126 miles.

Answer 2

126 miles

Explanation:

You want to know the distance traveled if it takes 3 hours less time at 21 mph than at 14 mph.

Time

The relation between time (t), speed (r), and distance (d) is ...

t = d/r

Using this relation we can write the time difference for a distance d and the given speeds as ...

d/14 -d/21 = 3

3d -2d = 3(42) = 126 . . . . multiply by the least common denominator, 42

d = 126

They traveled 126 miles.

<95141404393>