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the base of an isosceles triangle is 24 cm and its area is 192 sq. cm. what is the length of the equal sides of the triangle?

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5 votes

Answer:

Explanation:

Area of an isosceles triangle, using base and height: Area = ½ × b × h ·

192 sq. cm = ½ x 24 cm x h

192 sq. cm = 12 cm x h

h= 192 sq cm/ 12 cm

h= 16 cm

Remember the rule "The height drawn from the apex of an isosceles triangle divides the base into two equal parts and also divides the apex angle into two equal angles." These triangles are now , two congruent right-angled triangles.

If you imagine the right triangle, we know the sides and we need to find hypotenuse ( one side of the triangle).

So sides are 16, 12 (half of the base) and we are looking for hypotenuse using a^2 + b^2 = c^ 2.

16 ^2 + 12^2 = hypotenuse ^ 2

256 + 144 = hypotenuse ^ 2

400 = hypotenuse ^ 2

where hypotenuse is 20.

answered
User Sohail Ashraf
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