To calculate the density of the irregular-shaped chunk of iron, you can use the formula for density:
Density (D) = Mass (M) / Volume (V)
First, let's find the change in volume of water when the iron is placed in it:
Change in Volume = Final Volume - Initial Volume
Change in Volume = 49.10 ml - 45.5 ml = 3.60 ml
Now, we need to find the volume of the irregular-shaped chunk of iron. Since the chunk of iron displaces water, the volume of the iron is equal to the change in water volume:
Volume of Iron (V_iron) = Change in Volume = 3.60 ml
Next, we need to convert this volume to cubic centimeters (cc) since the mass is given in grams, and 1 ml is equivalent to 1 cc:
Volume of Iron (V_iron) = 3.60 cc
Now, you can calculate the density of iron:
Density (D) = Mass (M) / Volume (V)
Density (D) = 28.5 g / 3.60 cc
Density (D) ≈ 7.92 g/cc
So, the density of the irregular-shaped chunk of iron is approximately 7.92 grams per cubic centimeter (g/cc).