Question

Evaluate g(n-7) if g(x) = x^2-6 / 7x

Answer 1

g(n - 7) =
`(n^2-14n+43)/(7n-49)`

Explanation:

to evaluate g(n - 7) , substitute x = n - 7 into g(x)

g(x) =
`(x^2-6)/(7x)` , then

g(n - 7 ) =
`((n-7)^2-6)/(7(n-7))` ( expand (n - 7)² using FOIL

=
`(n^2-14n+49-6)/(7n-49)`

=
`(n^2-14n+43)/(7n-49)`