Answer:
1 on 286
Explanation:
The probability of selecting the three youngest students from a group of 13 available students can be calculated using the concept of combinations. Since we want to select 3 students from a group of 13, the total number of possible combinations is given by 13 choose 3, which can be calculated as (13!)/(3!(13-3)!). The factorial symbol (!) represents the product of all positive integers less than or equal to the given number. Simplifying this expression, we get (13*12*11)/(3*2*1) = 286. Therefore, there are 286 possible combinations of selecting 3 students from a group of 13. Since we want to select the three youngest students, there is only 1 combination that satisfies this condition. Therefore, the probability of selecting the three youngest students is 1/286.