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Answer:
b. 12 and 13
Explanation:
let x be the 1st number and x + 1 is the 2nd number
x(x+1) = 156
x² + x - 156 = 0
(x+13)(x-12)=0
x+13=0
x = -13
x-12=0
x = 12
∴ the 1st number is 12 and the second number is 13